x^2+.6x=4.36

Solution for x^2+.6x=4.36 equation:

x^2+.6x=4.36

We move all terms to the left:

x^2+.6x-(4.36)=0

We add all the numbers together, and all the variables

x^2+.6x-4.36=0

a = 1; b = .6; c = -4.36;
Δ = b2-4ac
Δ = .62-4·1·(-4.36)
Δ = 17.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.6)-\sqrt{17.8}}{2*1}=\frac{-0.6-\sqrt{17.8}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.6)+\sqrt{17.8}}{2*1}=\frac{-0.6+\sqrt{17.8}}{2}
$